Math, asked by Datlolboi, 9 months ago

Hey can someone answer this question and explain the method(s) to solve these types of questions. Thank you.​

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Answers

Answered by shristirajpoot789
1

Answer:

(4-2x-1)/2-x

3-2x/2-x

2-2+x/3-2x

6-4x-2+x/3-2x

4-3x/3-2x

1/4-3x/3-2x

3-2x/4-3x=x(this can be the answer or u can further solve it)

4x-3x²=3-2x

0=3x²-6x+3

0=3x²-3x-3x+3

3x(x-1)-3(x-1)=0

x=1,1

Step-by-step explanation:

in these questions just start from the base sove and just start solving towards upper part

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