Question

hey, can you please solve this question? ​

Answer 1

$\large\underline{\sf{Solution-}}$

a (i) 3 right angles starting from 6.

We know,

1 right angle = 1/4th of revolution

Therefore, 3 right angles = 3/4th of a revolution.

$\sf{ \frac{3}{4} \times 12hrs }$

$\sf{ = 3 \times 3hrs}$

$\sf{ = 9hrs}$

Hence, the hour hand of the clock will stop at 3.

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(ii) 3 right angles starting from 8.

Using the same method as used above,

$\sf{ \frac{3}{4} \times 12hrs }$

$\sf{ = 3 \times 3hrs}$

$\sf{ = 9 \: hrs}$

Hence, the hour hand of the clock will stop at 5.

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b (i) 2 right angles starting from 10.

We know,

1 right angle = 1/4th of revolution

Therefore, 2 right angles = 2/4th of a revolution.

$\sf{ \frac{2}{4} \times 12hrs}$

$\sf{ = 2 \times 3hrs}$

$\sf{ = 6hrs}$

Hence, the hour hand will stop at 4.

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(ii) 2 right angles starting from 12.

Using the above method,

$\sf{ \frac{2}{4} \times 12hrs}$

$\sf{ = 2 \times 3hrs}$

$\sf{ = 6hrs}$

Hence, the hour hand will stop at 6.

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c (i) 1 right angle starting from 5.

We know,

1 right angle = 1/4th of revolution

$\sf{ \frac{1}{4} \times 12hrs}$

$\sf{ = 1 \times 3hrs}$

$\sf{ = 3hrs}$

Hence, the hour hand will stop at 8.

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(ii) 1 right angle starting from 7.

Using the above method,

$\sf{ \frac{1}{4} \times 12hrs}$

$\sf{ = 1 \times 3hrs}$

$\sf{ = 3hrs}$

Hence, the hour hand will stop at 10.

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