Question

Hey could I get help with this question.
thanks​

Answer 1

Given :-

• BC || DE

Solution :-

Here,

BC || DE

Therefore,

Area of ΔCBE = Area of ΔCBD. eq( 1 )

[ Triangles on the same base and between the same parallel lines are equal ]

Now,

In ΔABE

Area of ΔABE = Area of ΔABC + Area of ΔCBE

Now,

In eq ( 1 ) , We know that,

Area of ΔCBE = Area of ΔCBD

Therefore,

Area of ΔABE = Area of ΔABC+ΔCBD( 2 )

From the given figure,

We observed that,

Area of ΔABC + Area of ΔCBD =Area of ΔABD ( 3 )

From ( 2 ) and ( 3 )

Area ΔABE = Area ΔACD $.$

Answer 2

Answer:

$\huge \underline \mathfrak \purple{Given}$

◆ BC || DE

$\huge \underline \mathfrak \red{Solution}$

Here,

BC || DE

Therefore,

Area of ΔCBE = Area of ΔCBD. eq( 1 )

[ Triangles on the same base and between the same parallel lines are equal ]

Now,

In ΔABE

Area of ΔABE = Area of ΔABC + Area of ΔCBE

Now,

In eq ( 1 ) , We know that,

Area of ΔCBE = Area of ΔCBD

Therefore,

Area of ΔABE = Area of ΔABC+ΔCBD( 2 )

From the given figure,

We observed that,

Area of ΔABC + Area of ΔCBD =Area of ΔABD ( 3 )

From ( 2 ) and ( 3 )

Area ΔABE = Area ΔACD