Question

Hey dear brainly stars
Answer this question plzz
5 and 9 today only otherwise it will be of no use

Answer 1

Heya!
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✒Linear Equations in One Variable✒
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$|5| \: \: \frac{3x - 12}{4} = 30 - 2x \\ \\ = > cross \: multiplying \: the \: terms \: < = \\ \\ = > 120 - 8x = 3x - 12 \\ \\ = > 120 + 12 = 8x + 3x \\ \\ = > 132 = 11x \\ \\ = > x = \frac{132}{11} \\ \\ \\ = > x = 12 \\ .........................$




✒Verification ✒
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☝Put x = 12 in the Equation
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$= > \frac{3(12) - 12}{4} = 30 - 2(12) \\ \\ = > \frac{36 - 12}{4} = 30 - 24 \\ \\ = > \frac{24}{4} = 6 \\ \\ = > 6 = 6$


✔Hence Verified !
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$|9.| \: \: \frac{2}{3} (4x - 1) - (4x - \frac{1 - 3x}{2} ) = \frac{x - 7}{2} \\ \\ = > ( \frac{8x - 2}{3} ) - ( \frac{8x - (1 - 3x)}{2} ) = \frac{x - 7}{2} \\ \\ = > ( \frac{8x - 2}{3} ) - ( \frac{11x - 1}{ 2} ) = \frac{x - 7}{2} \\ \\ = > \frac{16x - 4 - 33x + 3}{6} = \frac{x - 7}{2} \\ \\ = > \frac{ - 17x - 1}{6} = \frac{x - 7}{2} \\ \\ = > - 34x - 2 = 6x - 42 \\ \\ = > -3 4x - 6x = - 42 + 2 \\ \\ = > - 40x = - 40 \\ \\ = > x = 1 \\ \\ .....................$


✒Verification ✒
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☝Put x = 1 in the Equation
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$= > \frac{2}{3} (4 - 1) - (4 - ( \frac{1 - 3}{2} )) = \frac{1 - 7}{2} \\ \\ = > \frac{2}{3} \times 3 - (4 + 1) = \frac{ - 6}{2} \\ \\ = > 2 - 5 = - 3$


=> -3 = -3


✒Hence Verified !
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Answer 2

✌✌HERE IS YOUR ANSWER..⬇⬇

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5. $\underline{SOLUTION}$ ➡

$\frac{3x - 12}{4} = 30 - 2x \\ \\ = > 4(30 - 2x) = 3x - 12 \\ \\ = > 120 - 8x = 3x - 12 \\ \\ = > - 8x - 3x = - 12 - 120 \\ \\ = > - 11x = - 132 \\ \\ = > 11x = 132 \\ \\ = > x = \frac{132}{11} \\ \\ = > x = 12$

✒$\underline{ANSWER}$ ➡ x = 12

$\underline{VERIFICATION}$ ➡

By putting the value of x = 12 in the equation ➡

$L.H.S. = \frac{3x - 12}{4} \\ \\ = \frac{3 \times 12 - 12}{4} \\ \\ = \frac{36 - 12}{4} \\ \\ = \frac{24}{4} \\ \\ = 6 \\ \\ \\ \\ R.H.S. = 30 - 2x \\ \\ = 30 - 2 \times 12 \\ \\ = 3 0- 24 \\ \\ = 6 \\ \\ \\ So, \:L.H.S. = R.H.S.$

✅✅Hence verified the answer.

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9. $\underline{SOLUTION}$ ➡

$\frac{2}{3} (4x - 1) - (4x - \frac{1 - 3x}{2} ) = \frac{x - 7}{2} \\ \\ = > \frac{8x - 2}{3} - ( \frac{8x - (1 - 3x)}{2} ) = \frac{x - 7}{2} \\ \\ = > \frac{8x - 2}{3} - ( \frac{8x - 1 + 3x}{2} ) = \frac{x - 7}{2} \\ \\ = > \frac{8x - 2}{3} - \frac{11x - 1}{2} = \frac{x - 7}{2} \\ \\ = \frac{2(8x - 2) - 3(11x - 1)}{6} = \frac{x - 7}{2} \\ \\ = > \frac{16x - 4 - 33x + 3}{6} = \frac{x - 7}{2} \\ \\ = > \frac{ - 17x - 1}{6} = \frac{x - 7}{2} \\ \\ = > 2( - 17x - 1) = 6(x - 7) \\ \\ = > - 34x - 2 = 6x - 42 \\ \\ = > - 34x - 6x = - 42 + 2 \\ \\ = > - 40x = - 40 \\ \\ = > x = \frac{ - 40}{ - 40} \\ \\ = > x = 1$

✒ $\underline{ANSWER}$ ➡ x = 1

$\underline{VERIFICATION}$ ➡

By put the value of x = 1 in the equation ➡

$L.H.S. = \frac{2}{3}(4x -1 ) - (4x - \frac{1 - 3x}{2} ) \\ \\ = \frac{2}{3} (4 \times 1 - 1) - (4 \times 1 - \frac{1 - 3 \times 1}{2}) \\ \\ = \frac{2}{3} (4 - 1) - (4 - \frac{1 - 3}{2} ) \\ \\ = \frac{2}{3} \times 3 - (4 - \frac{( - 2)}{2} ) \\ \\ = 2 - \frac{8 + 2}{2} \\ \\ = 2 - \frac{10}{2} \\ \\ = \frac{4 - 10}{2} \\ \\ = \frac{ - 6}{2} \\ \\ = - 3 \\ \\ R.H.S.= \frac{x - 7}{2} \\ \\ = \frac{1 - 7}{2} \\ \\ = \frac{ - 6}{2} \\ \\ = - 3 \\ \\ \\ So ,\: L.H.S. = R.H.S$

✅✅Hence verified the answer.

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✝✝..HOPE IT HELPS YOU..✝✝