Question

Hey dear friends !!

Here's a math question for y'all .


Find the value of :-

1 + 1 - 1 + 1 - 1 + 1 - 1 + .....upto infinity


Thanks'

Answer 1

Hey fab


Here is it's solution .

1 + 1 - 1 + 1 - 1 + ......upto infinity .
Let infinity be n .
So , n can be even also or odd also .

When n = even
then this equation will be 0 .

Whne n = odd
the this equation will be 1 .

Now taking average of both conditions we get ,

0 + 1 / / = 1 / 2

♦ Answer ♦


One method is also there .

Umm ...let take this sum be S .
So , 1 + 1 - 1 + 1 - 1 + 1 - 1 + ......n = S
Subtact both sides from 1 .
=> 1 - S = 1 - [ 1 + 1 - 1 + ......n ]
=> 1 - S = 1 - 1 + 1 - 1 + 1 -1 + ....n
=> 1 - S = S
=> 1 = 2S
=> 2S = 1
=> S = 1 / 2


♦Answer ♦


thanks :)

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