Question

Hey dear users⤵⤵⤵
Question: How much ice at (0 degrees Celsius) must be added to 1.0 kg of water at 100 degrees Celsius to end up with all liquid at 20 degrees Celsius?

Answer 1

☜☆☞ hey friend ☜☆☞

here is your answer ☞
________

When two different phases are mixed together we calculate by,

m1CP1(Th - Tf) =m2CP2(Tf - TL)

​where,

Here 

CP1 is specific heat capacity of Steam = 1.996 J/K-g

CP2 is the specific heat capacity of Ice = 2.108​ J/K-g

Th = 100oC = 373 K

Tf  is the final temperature after mixing

TL= 0 oC = 273 K

m1CP1(Th - Tf) =m2CP2(Tf - TL)

X × 1.996 (373 - 273) = 1000×2.108(373 - 293)

X × 199.6 = 2.108×80×1000

X = 2.108 × 80× 1000/199.6 = 0.85×1000g

X = 0.85 kg ______answer

hope it will help you..

hope it will help you

Answer 2

Answer:

ᴛᴡᴏ ᴅɪғғᴇʀᴇɴᴛ ᴘʜᴀsᴇs ᴀʀᴇ ᴀᴛᴛᴀᴄʜᴇᴅ