Hey dude ...! help me....! Write this set in the roster method .X = { x/x is an even number , 1 < x < 8 }
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In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides of the triangle.
Now,
In a right triangle, side opposite to the 90° is always the hypotenuse. The square of the side opposite of the 90° in a right triangle is equal to the sum of squares of the other two sides.
Here,
∆ ABC is a right triangle, right angled at B. AC is the hypotenuse of the right ∆ ABC.
So, the square of AC = the sum of the squares of the other two sides AB and BC.
that is, AC² = AB² + BC²
or, hypotenuse (h)² = perpendicular (p) ² + base (b)² [Pythagoras Theorem]
Hence, proved.
Step-by-step explanation:
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