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plz answer question 6-9.
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Explanation:
9. Average speed is = L / ( t1+ t2)
t1 = L /(2 v1) & t2 = L /(2 v2)
L/ ( t1+ t2) = 2v1v2/ ( v1+ v2)
Average speed is 2 v1v2 / ( v1 + v2)
or
9.v1=L/2/t1,v2=L/2/t2
L=2v1t1,L=2v2t2
t1=L/2v1,t2=L/2v2
Vavg=total distance/total time=L/(L/2v1+L/2v2)
Vavg=(L/L/2)*1/(1/v1+1/v2)=2v1v2/v1+v2
6.The angle made by the given vector will be 45°
solution
From a general form of vector written as vector , when the given vector is compared,
We get,
x = 1
and
y = 1
And we know,
where θ is the angle made by the vector with x axis.
Hence, the angle (θ) made by the vector with the x-axis is 45°.
Vavg=(2v1v2)/(v1+v2)
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