Physics, asked by shivimishra3843, 10 months ago

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from a uniform circular disc of radius R a circular disc of radius R/6 and having centre at distance R/2 from centre of the disc is removed. center of mass of remaining portion of disc is at......​

Answers

Answered by cosmiccreed
3

Answer:

Suppose them mass per unit area of the disk be m

Mass of the disk

M=πR 2

m

Mass of the portion removed,

M =π( 6R ) 2

m= 36πR 2 m

Suppose M and M' are connected at the center O and O'

As the portion is removed taking M' as negative, center of moment of remaining portion is at a distance x from the O

x= M−M

Mx 1 −M ′ x 2

x= M−M

M×0−M

′ (R/2)

x=− 70R

Negative sign indicate that center of moment is lies left to the origin O.

Answered by rtarunraj29
0

Answer:

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