Math, asked by shalu2907bly, 8 months ago

Hey everyone help me to solve this quadratic equation i.e. 10R²-R-103=0.



Help me to get this answer right and i will mark u brainliest.​

Answers

Answered by atahrv
2

Step-by-step explanation:

We have,

10R²-R-103=0

First check that it have real roots or not.

Discriminant⇒b²4ac ,where a=10, b=(-1),c=(-103)

⇒(-1)²-4(10)(-103)

⇒1+4120

4121

b²-4ac>0, i.e. it have real and unequal roots.

This quadratic equation is solved in the attachment.

(Note:- You have to replace x to R)

Attachments:
Answered by yaduvanshitab
4

We have,

10R²-R-103=0

First check that it have real roots or not.

Discriminant⇒b²4ac ,where a=10, b=(-1),c=(-103)

⇒(-1)²-4(10)(-103)

⇒1+4120

⇒4121

∴ b²-4ac>0, i.e. it have real and unequal roots.

This quadratic equation is solved in the attachment.

(Note:- You have to replace x to R)

Attachments:
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