Question

Hey everyone I have 3 Questions.

1- Find the equation of the perpendicular bisector of the segment joining the points (−3,−2)and (5,−1).

2- Find the equation of the perpendicular bisector of the segment joining the points (8,−6)and (−4,5).

3- Find the equation of the straight line that passes through the points P(4,7) and Q(−12,7).

Give your answer in the form y=mx+c.

Answer 1

Answer:

MATHS

Find the equation of perpendicular bisector of the line segment joining the points A(2,3) and B(6,−5).

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ANSWER

Since, the slope of the line AB

=

x

2

−x

1

y

2

−y

1

=

6−2

−5−3

=

4

−8

=−2

But slope of perpendicular bisector will be

=−

m

1

=

2

1

Therefore, the equation of the line

y+1=

2

1

(x−4)

2y+2=x−4

x−2y=6