Math, asked by niharika2678, 1 year ago

hey everyone i m new here
plzz help me with question no. 13​

Attachments:

niharika2678: hey
niharika2678: want what?

Answers

Answered by Anonymous
6

REFER TO THE ATTACHMENT ❤️

Attachments:

Anonymous: yes?
dhvanit53: sry @dipali because of this idiot person
dhvanit53: i will text you in different answer
dhvanit53: plz inbox a message
vedthakar: @dipali you must improve your handwriting
vedthakar: because it matters in exams
Answered by Needthat
0

x = 9 - 4 \sqrt{5}  \\  \\  {x}^{2}  =  {9}^{2}  - 2(9)(4 \sqrt{5} ) +  {(4 \sqrt{5} )}^{2}  \\  \\  {x}^{2}  = 161 - 72 \sqrt{5}  \\  \\  \frac{1}{x}  =  \frac{1}{9 - 4 \sqrt{5} }  \\  \\  \frac{1}{x}  =  \frac{1}{(9 - 4 \sqrt{5} )}  \frac{(9 + 4 \sqrt{5} )}{(9 + 4 \sqrt{5} ) }  \\  \\  \frac{1}{x}  = 9 + 4 \sqrt{5}  \\  \\  \frac{1}{ {x}^{2} }  = 161 + 72 \sqrt{5}  \\  \\  {x}^{2}  +  \frac{1}{ {x}^{2} }  = 322

hope it helps


khushi121003: What's the answer then?
khushi121003: Is it 2...?
niharika2678: its 322
khushi121003: So you have got the right answer i guess....
niharika2678: yess i have
khushi121003: And that too twice
niharika2678: yaa
khushi121003: All right then....good night.
niharika2678: gud night
niharika2678: have a sweet dream
Similar questions