HEY EVERYONE!!
YOUR QUESTION IS IN THE ATTACHMENT. PLEASE HELP ME IN SOLVING THIS....
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jharoshan06466:
for what
frm assam
ulta pulta ans dene K liye
okay
so u r student???
hm
which class
10th. board xms de rhi hu
achaaa
hmmm
Answers
Answered by
2
See the attachment..
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Mark as brainliest plz
ohk
Ty
wella
yo
Hii N.D. ji means Naina Deko
how are you
what was your result
I had missed you very much in the last 2 months
so sorry
Answered by
1
Answer:
for (i) 13.5 ohms
2 -parallel
1 - series
r equalent = 13.5 ohms
for (ii) 6 ohms
2 - series
1 - parallel
r equalent = 6 ohms
Explanation:
for (i) 13.5 ohms
connect 2 resistors in parallel & 1 in series to them ,then resultant redistance is as below :
2 -parallel
1 - series
r equalent = [(9 x 9)÷(9+9)] + 9
= [ 81 ÷ 18] + 9
= 13.5 ohms
for (ii) 6 ohms
connect 2 resistors in series & 1 in parallel to them, then the resultant resistance be like...
2 - series
1 - parallel
r equalent = [ (9+9) x 9 ] ÷ (9+9) +9
= [18 x 9 ] ÷ 18 + 9
= 162 ÷27
= 6 ohms
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