Physics, asked by sahil1531, 1 year ago

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Answers

Answered by BrainlyHeart751
2

A particle is performing simple harmonic motion with time period T and Amplitude A. The time at which its displacement is A/1.41 is? A particle executes simple harmonic motion with time period of 16 sec. At that time t=2 sec, the particle crosses the mean position while at t= 4 sec, its velocity is 4 m/s.

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Answered by PSN03
3

the answer to your question is option D.T/12

i would recommend u to learn it as a fact

as its always asked in many exams


PSN03: i mean quality questions
PSN03: but my human nature has compelled me to answer you question.....so the answer would be T/4
PSN03: it would take T/4 to complete one amplitude or precisely to reach one maxima
PSN03: hope it helps dude
PSN03: i am always there for your every doubt
sahil1531: thanks a lot bro ☺
sahil1531: bro if you would go through my account you will find best quality question ❗
sahil1531: so please just go through it a time bro seriously they are conceptional ☺
BrainlyHeart751: question ?? what's the question??
PSN03: ok dude
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