Question

Hey!!!!!
Find order pair for (m,n)..
If m^2- n^2 = 14

Answer 1

Hi ...dear....
here is your answer...!!.....

Given,
n^2-m^2=14...


(.n+m)(n-m) = 7*2..


see picture...!!!..
by solving equations we get...
..(m,n)= (9/2,5/2 ) or (9/2 , -5/2)...
hope it helped you!!
Regards Brainly Star Community
#shubhendu

Answer 2

!! Hey Mate !!

your answer is ---

Given,

m^2 - n^2 = 14

=> (m+n) (m-n) = 7 × 2 [ using identity a^2 - b^2 = (a+b)(a-) ]

comparing both side , we get

m+n = 7 .....(1)
m-n = 2 ....(2)

adding equation (1)&(2) , we get

2m = 9

=> m =9/2

put this value in equation (1), we get

9/2+n =7

=> n = 7-(9/2)

=> n = 5/2

Now, Number of ordered pair of (m,n) is

m × n = 9/2×5/2 = 45/4



Hope it help you