Question

❤ HEY ❤

Find the reading of the spring balance shown in above attached figure. The elevator is going up with an acceleration of g/10, the pulley and the string are light and the pulley is smooth.✌

Answer 1

Answer:

4.4Kg

Explanation:

Here,we can think from non inertial frame of reference that as the lift is moving upward with an acceleration of g10,so net force acting downward for the two blocks will be their weight+(g/10)their mass.

So,if the tension in the string is T,we can write for the larger block as, 3g+3g10−T=3a (as it is going down)
similarly for the smaller block T−1.5g−1.5g10=1.5a (where, a is the acceleration of the blocks relative to the lift)
Solving both we get, T=(115)g
Now,the spring is attached to the pulley which is bearing the tension of the string from both the side,so the spring will show a reading of 2T=(225)g=43.12N
so,reading of the spring balance will be 22g5g=4.4Kg

Answer 2

Hey genius here your are