hey!!!
find the value of (-1)^n+(-1)^2n+1+(-1)^4n+1 where n is any positive odd integer
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Considering first term, (-1)^n
If n were odd, we'll always get (-1)
Considering second term, (-1)^2n+1
If n were odd, then odd×2 = even, even + 1 is odd, and (-1) raised to an odd power would yield (-1)
Considering third term, (-1)^4n+1
If n were odd, 4×n would be even, and even+1 = odd, so, (-1) to an odd power would always be (-1)
So, adding them up, we'll get,
(-1)+(-1)+(-1)
= (-3)
If n were odd, we'll always get (-1)
Considering second term, (-1)^2n+1
If n were odd, then odd×2 = even, even + 1 is odd, and (-1) raised to an odd power would yield (-1)
Considering third term, (-1)^4n+1
If n were odd, 4×n would be even, and even+1 = odd, so, (-1) to an odd power would always be (-1)
So, adding them up, we'll get,
(-1)+(-1)+(-1)
= (-3)
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