Hey!!
Find the value of x (red angle).
Answer above given question..
Options are:
a) 30°
b) 45°
C) 50°
d) 55°
Please solve it..
Don't want spam answer and only options.
Need full explanation.
^-^
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》☆》☆》Hope it'shelp you《《《
#Answer is also solve in picture if u have any doubts in pic then see following down☆☆☆
Connecting AC, we get AB = BC And∠BAC= ∠ACB and ∠ACB = ∠BCE+∠ECA = 45° Let ∠a=∠ECA as the two ∆ADC and ∆DFG are congruent (the triangle that has sides 3, 1 and 10−−√) So, ∠ECA=∠FDG=∠a [∆ADC≈∆DFG By SSS]In ∆DOC, ∠DOC=∠x [Vertically opposite angles]∠DOC+∠OCD+∠CDO=180°Finally, ∠x = 180° −(∠a + ∠BCD ) (∠OCD=∠BCD , ∠CDO=∠a , ∠DOC=∠x) = 180° − (∠a + ∠ECB + ∠ECD) = 180° − 90° − 45° = 45° So, ∠x = 45°Hence Option (B) 45° is correct
#Answer is also solve in picture if u have any doubts in pic then see following down☆☆☆
Connecting AC, we get AB = BC And∠BAC= ∠ACB and ∠ACB = ∠BCE+∠ECA = 45° Let ∠a=∠ECA as the two ∆ADC and ∆DFG are congruent (the triangle that has sides 3, 1 and 10−−√) So, ∠ECA=∠FDG=∠a [∆ADC≈∆DFG By SSS]In ∆DOC, ∠DOC=∠x [Vertically opposite angles]∠DOC+∠OCD+∠CDO=180°Finally, ∠x = 180° −(∠a + ∠BCD ) (∠OCD=∠BCD , ∠CDO=∠a , ∠DOC=∠x) = 180° − (∠a + ∠ECB + ∠ECD) = 180° − 90° − 45° = 45° So, ∠x = 45°Hence Option (B) 45° is correct
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grvbundela008p3f6id:
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