Question

Hey!!!!
Find the zeroes of
✌️

$x {}^{2} - x - 12$
​

Answer 1

Answer:

x^2 -x-12

x²-4x+3x-12

X(X-4)+3(x-4)

(x+3)(x-4)

two zero are

X=-3,4

hope this answer useful to you mate

Answer 2

Answer:

☺️Here's ur answer mate..

X^2- X - 12=0

X^2 + (3-4) X - 12=0

X^2 +3X - 4X - 12=0

X(X+3) - 4 (X+3)=0

Hence, the zeros for this eq^n. Are..

1. X= 4

2. X = - 3

HOPE IT HELPS

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