Question

Hey !!!

Find x if 2log5+1/2log9-log3=logx

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#Maths

Answer 1

Answer:

Step-by-step explanation:

$Hey!$

Logx = 2log5+1/2log9-log3

= log5^2+log9^1/2-log3

= log25+log root9- log3

=log25+log3-log3

Logx = log25

x = 25

Check attachment ^_^

Answer 2

$2 log5+ \frac{1}{ log(9) } - log3 = logx \\ \\ = > 2 log5 + \frac{1}{ log( {3}^{2} ) } - log3 = logx \\ \\ = > 2 log5 + \frac{1}{2 log3 } - log3 = logx \\ \\ = >2 \times 0.6989 + \frac{1}{2 \times 0.30103} - 0.47712 = logx \\ \\ = > 3.53588 = logx \\ \\ = > x = antilog \: 3.53588 \\ \\ = > x = 25$