Hey find x in the figure.
IT'S not a easy geometric problem it's the hardest
Answers
Hey there
Mark as BRAINLIST
If it helps you
Let's start
This is the one of the hardest easy looking geometric problem and i have got the solution for you
You need to do construction in it orelse you won't be able to do this question
Firstly we will calculate
some known angles:such as below ones
ACB = 180-(10+70)-(60+20) = 20 degree
AEB = 180-60-(50+30) = 40 degree
2. Draw a line from point E parallel to AB, labelling... the intersection with AC as a new point F and conclude:
FCE ACB
CEF = CBA = 50+30 = 80 degree
FEB = 180-80 = 100°
AEF = 100-40 = 60°
CFE = CAB = 60+20 = 80 degree
EFA = 180-80 = 100°
3. Draw a line FB showing the intersection with AE as a new point G and SAY THAT that :
AFE BEF
AFB = BEA = 40 degree
BFE = AEF = 60 degree
FGE = 180-60-60 = 60 degree = AGB.
ABG = 180-60-60 = 60 degree
4. Draw a line DG. Since AD=AB (leg of isosceles) and AG=AB (leg of equilateral), conclude:
AD = AG.
DAG is isosceles
ADG = AGD = (180-20)/2 = 80 degree
5. Since DGF = 180-80-60 = 40 degree, conclude:
FDG (with two 40 degree angles ) is isosceles, so DF = DG
6. With EF = EG (legs of equilateral) and DE = DE (same line segment) WE CAN SAY THAT:
DEF DEG by side-side-side rule
DEF = DEG = x
FEG = 60 = x+x
Answer: x = 30 degree