Question

Hey folks!

Explain this theorem : The angles subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle.

Do draw a diagram, for me to easily understand ^^"

Thank ya, in advance! :P

PS - Can't give more than 10 points. Will at least get 5 points for selecting the brainliest answer *laughs greedily* xD

Answer 1

Answer:

Step-by-step explanation:

If you consider minor arc AB, then the angle subtended by it at the centre is AOB

And let the other point be C

Then the angle subtended by minor arc AB at C is ACB

The theorem says that angle AOB is twice of angle ACB.

For eg. If angle ACB is 30° then angle AOB will be 2×30°= 60°

Refer to figure for better understanding

Hope this helps!

Answer 2

This theorem states that when the angle is subtended by an arc at the centre is double of the angle subtended from any remaining part of circle .

It means that whenever an angle is drawn or subtended at centre will always be double of angle subtended at any other point of circle.

In the firgure given

angle 2 = 2 (angle 1)

proof is given in the attachment

Hope it helps you :-P

Thanks