Question

hey friend ✋

please solve this question ↙↙

________________________
One root of a polynomial f(x) = bx^2 + 13x + 5 is reciprocal of the other, then the value of b is
________________________

NO SPAMMING PLEASE‼‼

★★ CONTENT QUALITY ANSWER REQUIRED ★★

Answer 1

$\color{Red}{Answer} \:$

$\color{blue}{thanks \: for \: asking \: this \: question}$

Solution:-

Let the given quadratic polynomial be p(x) 

(bx²+13x+5)

then,

Let to be a and 1/a zero of the above Polynomial.

Again,

Product of zeroes

5/b=1

b=5×1
b=5

Answer:- 5

$\bold{Sujeet \: kumar \: yaduvanshi}$