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A bag contains one rupee 50 paisa and 25 paisa coins in the ratio 5:6:8 amounting to rs.210 . Find the no.of coins of each type . Help me coz tomorrow is my EXAM...
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Nikitan:
Help me dear
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Answer:
105, 126, 672
Step-by-step explanation:
Given, Ratio of values = 5 : 6 : 8
= 5 : (6/2) : (8/4)
= 5 : 3 : 2
Given,Total = 210.
Divide 210 in the ratio of 5 : 3 : 2.
(i)
1st part = (210 * 5/10)
= 105
2nd part = (210 * 3/10)
= 63.
3rd part = (210 * 8/10)
= 168
Therefore,
Number of 1-rupee coins = 105.
Number of 50-paise coins = 63 * 2 = 126.
Number of 25-paise coins = 168 * 4 = 672.
Hope it helps!
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