Question

Hey friends ❤
A bag contains one rupee 50 paisa and 25 paisa coins in the ratio 5:6:8 amounting to rs.210 . Find the no.of coins of each type . Help me coz tomorrow is my EXAM...
I will mark u brainliest​

Answer 1

Answer:

105, 126, 672

Step-by-step explanation:

Given, Ratio of values = 5 : 6 : 8

                                     = 5 : (6/2) : (8/4)

                                     = 5 : 3 : 2

Given,Total = 210.

Divide 210 in the ratio of 5 : 3 : 2.

(i)

1st part = (210 * 5/10)

            = 105

2nd part = (210 * 3/10)

              = 63.

3rd part = (210 * 8/10)

             = 168

Therefore,

Number of 1-rupee coins = 105.

Number of 50-paise coins = 63 * 2 = 126.

Number of 25-paise coins = 168 * 4 = 672.

Hope it helps!

Answer 2

$\underline{\mathfrak{\huge{Answer}}}$

Given,

The ratio of Rs 1 : 50 paise : 25 paise

= 5:6:8

Total amount = RS 210

Now, The ratio :-

= 5 : (6/2) : (8/4)

= 5 : 3 : 2

Given,Total = 210.

Divide 210 in the ratio of 5 : 3 : 2.

(i)

1st part = (210 * 5/10)

= 105

2nd part = (210 * 3/10)

= 63.

3rd part = (210 * 8/10)

= 168

Therefore,

Number of 1-rupee coins = $\underline{\mathfrak{\huge{105}}}$

Number of 50-paise coins = 63 * 2 = $\underline{\mathfrak{\huge{126}}}$

Number of 25-paise coins = 168 * 4 = $\underline{\mathfrak{\huge{672}}}$

$\underline{\mathfrak{\huge{Thank You}}}$