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5. ANSWER :
◆ Given:
◆The area of a parallelogram ABCD is 40 cm square.
◆pq is the median of ∆ CDP.
◆area of the ∆PDQ=?
◆ar(∆CDP)=1/2 (area of parallelogram ABCD)
◆=1/2 (40 cm square)
◆20 cm square
◆Therefore PQ is a median of ∆CDP.
◆ar(∆PDQ)=1/2×ar(∆CDP)
◆ar(∆PDQ)=1/2×(20 cm square) =10 cm square
◆Therefore the area of ∆ PDQ is 10 cm square.
❤I HOPE THIS HELPS YOU❤
☺PLEASE MARK IT AS BRAINLIEST.☺
5. ANSWER :
◆ Given:
◆The area of a parallelogram ABCD is 40 cm square.
◆pq is the median of ∆ CDP.
◆area of the ∆PDQ=?
◆ar(∆CDP)=1/2 (area of parallelogram ABCD)
◆=1/2 (40 cm square)
◆20 cm square
◆Therefore PQ is a median of ∆CDP.
◆ar(∆PDQ)=1/2×ar(∆CDP)
◆ar(∆PDQ)=1/2×(20 cm square) =10 cm square
◆Therefore the area of ∆ PDQ is 10 cm square.
❤I HOPE THIS HELPS YOU❤
☺PLEASE MARK IT AS BRAINLIEST.☺
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