Question

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Answer 1

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Answer:

Given:-

1. ∆ PQR is an isosceles triangle.
2. PQ = PR
3. angle PQR = 40°
4. PS is the median.

To find :-

1. angle QPS

Solution:-

• angle PQS = angle PRS = 40° ( angles on the equal sides of a triangle are equal )
• angle QPR = 180° - 80° = 100° ( Angle Sum Property of a Triangle )
• angle QPS = 1/2 angle QPR ( PS is the median and PS bisects angle P )
• angle QPS = 100° / 2 = 50°

Hence, the value of angle QPS is 50°.

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