Math, asked by Ramlayaksingh3, 11 months ago

hey friends .

can anyone explain me this step ?

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Answered by vanshgenius2004
2

Answer:

 {k}^{2}  - 24 \geqslant 0 \\  {k}^{2}  \geqslant 24 \\ k \geqslant  \sqrt{24}  \\ k \geqslant  \sqrt{2 \times 2  \times 2\times 3}  \\ k \geqslant 2 \sqrt{2 \times 3}  \\ k \geqslant 2 \sqrt{6}

Hope it helps...

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