Question

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Answer 1

Answer:

Step-by-step explanation:

let bd be x

bc= 1000-x

in triangle abd

tan 30= h/x

$1/\s\sqrt3$=h/x

$x= h\sqrt3$.........1

in triangle abc

tan 60=h/ 1000-x

$\sqrt3=h/1000-x$

$1000\sqrt3-h/\sqrt3=x$..........2

from 1 and 2

$1000\sqrt3-h/\sqrt3=h\sqrt3$

$1000\sqrt3=4h$

$250\sqrt3=h$

Answer 2

HERE IS YOUR ANSWER:-

Let DB = x and BC = 1000-x

Tan30 = h/x

$h = x \div \sqrt{3}$

Tan60 = h/1000-x

$h = 1000 \sqrt{3} - x \sqrt{3}$

Therefore,

$x \div \sqrt{3} = 1000 \sqrt{3} - x \sqrt{3 } \\ x = 3000 - 3x \\ 4x = 3000 \\ x = 750 \\ h = 750 \div \sqrt{3} \\ h = 250 \sqrt{3}$