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Here's my question ⭐⭐
A BULLET OF MASS 20g IS HORIZONTALLY FIRED WITH A VELOCITY 150m per second square FROM A PISTOL OF MASS 2kg WHAT IS THE RECOIL VELOCITY OF THE PISTOL?
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Answered by
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For this question we will use consevasion of momentum -
m1v1 +m2v2 = m1u1 + m2u2
m1 = 20g = 0.020 kg = 20/1000 kg
u1 = 0m/s
v1 = 150m/s
m2 = 2 kg
u2 = 0m/s
v2 = unknown = v
= [ 20/1000 * 150 ] + [ 2v ] = [ 20/1000*0] + [ 2 * 0 ]
= 3 + 2v = 0
= 2v = -3
= v = -3/2
= v = -1.5m/s
ANS ---- recoil velocity of the pistol is -1.5m/s
m1v1 +m2v2 = m1u1 + m2u2
m1 = 20g = 0.020 kg = 20/1000 kg
u1 = 0m/s
v1 = 150m/s
m2 = 2 kg
u2 = 0m/s
v2 = unknown = v
= [ 20/1000 * 150 ] + [ 2v ] = [ 20/1000*0] + [ 2 * 0 ]
= 3 + 2v = 0
= 2v = -3
= v = -3/2
= v = -1.5m/s
ANS ---- recoil velocity of the pistol is -1.5m/s
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