Hey friends I couldn't get the solution please help me
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Radius =32 cm
AO=2/3,AD32
Then,
AB^2=AD^2+BD^2
AB^2=48^2+AB/2^2
3AB^2/4=48^2
AB=48*2/√3=96/√3
=32√3
ΔABC=√3/4*32*32*3=96*8*√3
=768√3
Circle of area=πr^2
=22/7*32^2
=22/7*1024
=22528/7
So,
Area of design=Area of circle - Δ ABC Area
=22528/7-768√3
By
Aanya Kandwal
Radius =32 cm
AO=2/3,AD32
Then,
AB^2=AD^2+BD^2
AB^2=48^2+AB/2^2
3AB^2/4=48^2
AB=48*2/√3=96/√3
=32√3
ΔABC=√3/4*32*32*3=96*8*√3
=768√3
Circle of area=πr^2
=22/7*32^2
=22/7*1024
=22528/7
So,
Area of design=Area of circle - Δ ABC Area
=22528/7-768√3
By
Aanya Kandwal
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