Question

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Question - Specific heat of an unknown metal is 0.08 calg⁻¹k⁻¹ . If the equivalent mass of the metal is 13 then the exact atomic mass will be?

Option 1 > 78 Option 2 > 80
Option 3 > 52 Option 4> 10.4

Please show the whole and correct procedure for the answer and derive formulas which are required. No Spamming - 25 marks awarded for a good answer

Answer 1

Answer:

Given:

Specific heat = 1 J/gK

= 0.22 cal/g/mol

Equivalent weight = 9

By using Dulong Petit law,

Approximate atomic mass = 6.4 / Specific heat

=6.4/ 0.22

= 29.09 g

Valency = Approximate atomic mass / Equivalent weight

= 29.09 / 9

= 3.23

=3

Exact atomic weight = Equivalent weight × Valency

= 9× 3

= 27

Exact atomic weight of metal is 27 g.

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