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Question - Specific heat of an unknown metal is 0.08 calg⁻¹k⁻¹ . If the equivalent mass of the metal is 13 then the exact atomic mass will be?
Option 1 > 78 Option 2 > 80
Option 3 > 52 Option 4> 10.4
Please show the whole and correct procedure for the answer and derive formulas which are required. No Spamming - 25 marks awarded for a good answer
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Answer:
Given:
Specific heat = 1 J/gK
= 0.22 cal/g/mol
Equivalent weight = 9
By using Dulong Petit law,
Approximate atomic mass = 6.4 / Specific heat
=6.4/ 0.22
= 29.09 g
Valency = Approximate atomic mass / Equivalent weight
= 29.09 / 9
= 3.23
=3
Exact atomic weight = Equivalent weight × Valency
= 9× 3
= 27
Exact atomic weight of metal is 27 g.
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