Question

Hey Friends♥

Please answer it...

Don't spam ×××



​

Answer 1

$\huge\pink{Solution}$

According to Fundamental Theorem of Arithmetic,

${12}^{n} = {2}^{n} \times {2}^{n} \times {3}^{n}$

We know that,

To end with the digit 0 or 5, it must 5 as one of its factors.

But here, there is no any 5 in its factor.

So, It can never end with digit 5 or 0.

$\large\red{Hope}$$\large\red{it}$$\large\red{helps}$

Answer 2

solution is attached above......