Question

Hey friends !!
Please answer the above ☝ question​

Answer 1

Answer:

let roots be a and b

So sum of roots =a+b= -coefficient of x/coefficient of x²

And product of roots = ab= constant/coefficient of x²

Here coefficient of x is -8

And constant is 2

While coefficient of x² is 1

so a+b= -(-8)/1 = 8

and ab= 2/1 = 2

(a-b)²= (a+b)²-4ab

so now a-b = √(a-b)² = √(a+b)²-4ab

a-b = √8²-4*2 = √64-8 = √56 = 2√14

So your answer is 2√14

hope it helps please mark me brainliest!!

Answer 2

Step-by-step explanation:

the sum of roots is

a + b = 8

and product of roots

a * b = 2

now squaring the sum of roots

a² + b² + 2ab = (a + b)²

a² + b² = 64 - 2 * 2 = 60

and

a² + b² - 2ab = (a - b)²

60 - 4 = (a - b)²

a - b = √56