Math, asked by vrinda5715, 8 months ago

hey friends
please go to my profile ... go to question list their solve all the unanswered questions of Trigonometry please
but hereby too I'm giving u those two questions
I'm having the problem with calculations
no spam or I'll surely report​

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Answers

Answered by MysteriousAryan
14

Answer:

sin C = (Side opposite to ∠C)/(Hypotenuse) = AB/AC

cos C = (Side adjacent to ∠C)/(Hypotenuse) = BC/AC

tan C = (Side opposite to ∠C)/(Side adjacent to ∠C) = AB/AC = sin ∠C/cos ∠C

cosec C= 1/sin C = (Hypotenuse)/ (Side Opposite to ∠C) = AC/AB

sec C = 1/cos C = (Hypotenuse)/ (Side Opposite to ∠C) = AC/BC

cot C = 1/tan C = (Side adjacent to ∠C)/(Side opposite to ∠C)= BC/AB

Answered by Anonymous
1

Answer:

refer to the attachment

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