hey friends
please go to my profile ... go to question list their solve all the unanswered questions of Trigonometry please
but hereby too I'm giving u those two questions
I'm having the problem with calculations
no spam or I'll surely report
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Answered by
14
Answer:
sin C = (Side opposite to ∠C)/(Hypotenuse) = AB/AC
cos C = (Side adjacent to ∠C)/(Hypotenuse) = BC/AC
tan C = (Side opposite to ∠C)/(Side adjacent to ∠C) = AB/AC = sin ∠C/cos ∠C
cosec C= 1/sin C = (Hypotenuse)/ (Side Opposite to ∠C) = AC/AB
sec C = 1/cos C = (Hypotenuse)/ (Side Opposite to ∠C) = AC/BC
cot C = 1/tan C = (Side adjacent to ∠C)/(Side opposite to ∠C)= BC/AB
Answered by
1
Answer:
refer to the attachment
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