Question

Hey friends!!!
Please help.
If
${(3}^{2x +1} + 9) \div 9 = 10$
find the value of x.

Answer 1

hey there here is your answer

given
$({3}^{2x + 1} + 9) \div 9 = 10 \\ {3}^{2x + 1} + 9 = 10 \times 9 = 90 \\ {3}^{2x + 1} = 90 - 9 = 81 \\ {3}^{2x + 1 } = {3}^{4} \\ 2x + 1 = 4 \\ 2x = 4 - 1 = 3 \\ x = \frac{3}{2}$

hope it helps you

thanks

Answer 2

$\huge \underline \mathfrak {Solution:-}$

This qiven equation can be solved as follows to find out the value of x.

$( {3}^{2x + 1} + 9) \div 9 = 10$

On multiplying both sides by 9

$( {3}^{2x + 1} + 9) = 10 \times 9 \\ \\ ( {3}^{2x + 1} + 9) = 90$

On subtracting both sides by 9

${3}^{2x + 1} = 90 - 9 \\ \\ {3}^{2x + 1} = 81$

We know that, 81 = 3*3*3*3

${3}^{2x + 1} = {3}^{4} \\ \\ on \: comparing \: there \: powers \\ \\ 2x + 1 = 4 \\ \\ 2x = 4 - 1 \\ \\ 2x = 3 \\ \\ x = \frac{3}{2}$

So, the Value of x is 3/2.