Question

Hey friends please help me if you know the answer.I need it soon.
If a=1/a-5,find a-1/a, a+1/a, a^2-1/a^2

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Answer 1

Answer:

>>>> supposed to be the right answer in one method,

• If a-1/a=5 the a-1=5a
• -1=5a-a which is -1=4a which is a=-1/4 ————1
• a²-1/a² is (-1/4)² -1/(-1/4)² which is 1/16 -1/1/16.
• -15/16 / 1/16
• Applying another method from given condition in problem.
• Other right answer is a-1/a=5—Eq1
• So squaring both sides
• We get a² -2a/a +1/a² which is a² +1/a² -2=5×5
• Which further is a²+1/a²-2=25—Eq2
• Now adding 4 to both sides
• a²+1/a²-2+4=25+4
• Which is a²+2+1/a²=29
• Further square root of both sides
• √a²+2+1/a²=√29
• a+1/a=√29
• Now in problem the then asked what is a²-1/a² is (a+1/a)(a-1/a)
• a+1/a ×a-1/a
• Whereas in question a-1/a=5 and a+1/a=√29 is proved

So +-5√29 is Answer.

Step-by-step explanation:

good morning

Answer 2

$±5 \sqrt{29}$