Math, asked by sumantgiri49gmailcom, 1 month ago

hey friends please help me in this
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Answered by Equuleus
1

We solve this using Pythagoras.

We know that all 4 sides of a rhombus are equal.

So perimeter of rhombus = 4s

180 = 4s

s = 180/4

s = 45

Now, we can see that the diagonals of a rhombus split it into 4 right triangles.

We're given the length of one of the diagonals = 72 cm.

So we take half of it as one of the sides of a triangle = 72/2 = 36

Now, we have two sides of a right triangle, so we can find the third using pythagoras.

45^2 = 36^2 + x^2

x^2 = 45^2 - 36^2

x^2 = 729

x = √729

x = 27

So, the third side = 27

This third side is also half of the second diagonal, so the diagonal = 2x = 2*27 = 54

Now, for part 2 we have to find area of the rhombus.

Area of rhombus = (Diagonal * Diagonal)/2

= (72*54)/2

= 3888/2

= 1944u²

Hope this Helped!

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Answered by ayushanuraggupta89
2

Answer:

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