Question

hey friends please solve this problem. it's urgent ​

Answer 1

Answer:

The number of inhabitants at the end of 3 years will be 68921.

Step-by-step explanation:

No. of inhabitants in district = 64000

Rate = 2 1/2 percent = 5/2 percent

Time = 3

64000[1+5/2 ×100]³

= 64000 [1 + 5/200]³

= 64000 [1 + 1/40]³

= 64000 × 41/40 × 41/40 × 41/40

= 64 × 41/4 × 41/4 × 41/4

= 41 × 41 × 41

= 68921

Hence, the number of inhabitants at the end of 3 years will be 68921.

HOPE IT HELPS U!

MARK AS BRAINLIEST!

Answer 2

Step-by-step explanation:

$solution \: \: \\ \\ population \: after \: 3 \: years \: = \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 64000 {(1 + \frac{ \frac{5}{2} }{100} )}^{3} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 64000 {(1 + \frac{1}{40 }) }^{3} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 64000 \times \frac{41}{40} \times \frac{41}{40} \times \frac{41}{40} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 68921 \\ \\ hope \: it \: will \: help \: you \:$