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Answered by
3
Heya !!!
Given that,
(X + 2) is a factor of the given polynomial.
Therefore,
(X + 2) = 0
X = -2
P(X) = 4X⁴ + 2X³ - 3X² +8X +5A
P(-2) = 4 × (-2)⁴ + 2 × (-2)³ - 3 × (-2)² + 8 × -2 + 5A
=> 4 × 16 + 2 × -8 - 3 × 4 - 16 + 5A = 0
=> 64 - 16 - 12 - 16 + 5A = 0
=> 64 - 44 + 5A = 0
=> 5A = -20
=> A = -20/5
=> A = -4
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
Given that,
(X + 2) is a factor of the given polynomial.
Therefore,
(X + 2) = 0
X = -2
P(X) = 4X⁴ + 2X³ - 3X² +8X +5A
P(-2) = 4 × (-2)⁴ + 2 × (-2)³ - 3 × (-2)² + 8 × -2 + 5A
=> 4 × 16 + 2 × -8 - 3 × 4 - 16 + 5A = 0
=> 64 - 16 - 12 - 16 + 5A = 0
=> 64 - 44 + 5A = 0
=> 5A = -20
=> A = -20/5
=> A = -4
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
Kashyap360:
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Answered by
0
Given that (x + 2) is the factor,
So, x + 2 = 0
x = -2
××××××××××××××××××
Putting the value of x in the given equation :
4x⁴ + 2x³ - 3x² + 8x + 5a = 0
4(-2)⁴ + 2(-2)³ - 3(-2)² + 8(-2) + 5a = 0
4(16) + 2(-8) -3(4) + 8(-2) + 5a = 0
64 - 16 - 12 - 16 + 5a = 0
64 - 44 + 5a = 0
20 + 5a = 0
5a = -20
I hope this will help you
(-:
So, x + 2 = 0
x = -2
××××××××××××××××××
Putting the value of x in the given equation :
4x⁴ + 2x³ - 3x² + 8x + 5a = 0
4(-2)⁴ + 2(-2)³ - 3(-2)² + 8(-2) + 5a = 0
4(16) + 2(-8) -3(4) + 8(-2) + 5a = 0
64 - 16 - 12 - 16 + 5a = 0
64 - 44 + 5a = 0
20 + 5a = 0
5a = -20
I hope this will help you
(-:
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