Question

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Three pipes A, B and C can fill a cistern in 8 hours . After working together for 2 hours , A is closed and B and C can fill it in 9 hours . The number of hours taken by A alone to fill the cistern ..???
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Answer 1

Answer:

24 hours.

Given,

A,B,C can fill a cistern in 8 hours. working together for 2 hours, A is closed and B and C fill it in 9 hours.

To Find,

Number of hours taken by A alone.

Solution,

A,B,C can fill a cistern in 8 hours.

==> Part filled by A,B,C in 1 hour = (1/8).

After working 2 hours{All these pipes are open only for 2 hours}.

==> Part filled by A,B,C in these 2 hours = 2/8 = 1/4.

Remaining part = 1 - 1/4 = 3/4.

After working or 2 hours, A is closed.

So, This remaining part of 3/4 is filled by B and C in 9 hours.

==> Part filled by B and C in 1 hour = (3/4)/9 = 3/36 = 1/12

Then,

Part filled by A in 1 hour = (1/8 - 1/12) = 1/24

Thus, A alone can fill the cistern in 24 hours.

Result:

Time taken by A to fill the cistern = 24 hours.

#Hope my answer helped you.