Question

##hey friends plz help me to solve this problem ##
--》AB=AC & /_A is right angle in /\ ABC .
--》if BC=root 2 a , then find the area of /\ABC .@@@@@¿¿¿¿¿

Answer 1

AB = AC so given triangle is isoscles triangle

Side BC is hypotenus since angle A is right angle

so let AB = BC = x^2

BC = root 2a

Using Pythagoras theorem

( BC )^2 = ( AB )^2 + ( BC )^2

(root 2a )^2 = x ^2 + x^2

2a^2 = 2 x^2

a^2 = x^2

a = x

so area of triangle = 1/2 sides forming right angle

= 1/2 × a × a

= a^2/2

so area of triangle is a^2/2 units