Hey friends
To solve this quadratic equation by factorisation method
Answer is X = - under root 2 and -5/under root 2
you do not have any idea so please do not take answer.
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√2 x2 + 7x + 5√2
= √2 x2 + 5x + 2x + 5√2
= x (√2x + 5) + √2(√2x + 5)= (√2x + 5)(x + √2)
Roots of this equation are the values for which (√2x + 5)(x + √2) = 0
∴ √2x + 5 = 0 or x + √2 = 0
⇒ x = -5/√2 or x = -√2
Hope this helps you
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= √2 x2 + 5x + 2x + 5√2
= x (√2x + 5) + √2(√2x + 5)= (√2x + 5)(x + √2)
Roots of this equation are the values for which (√2x + 5)(x + √2) = 0
∴ √2x + 5 = 0 or x + √2 = 0
⇒ x = -5/√2 or x = -√2
Hope this helps you
Please! Mark as Brainliest
Priyanshu2000:
mark as brainliest
√2(√2x+5) priyanshu ha kay se aaya
2 can be written as the product of root 2 x root 2
Ok thanks bro
mark as brainliest
ok bro
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