Question

hey friends

want ur help

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@AARCHI

Answer 1

ILLUSTRATION :-
CONSIDER A THREE DIGIT NUMBER
243.
SO, 243 = 2×100+4×10+3
SIMILARLY, IF IT IS XYZ, THEN, XYZ = 100X+10Y+Z

ACTUAL SOLUTION AARCHIIIIIIIIIIII........^__^


Now, let the unit digit be x
Then the hundred digit = 4x

Similarly, let the tenth digit be y.
Then the number stands :
(100×4x) + (10y) + x


ACCORDING TO THE QUESTION ,

4x + y + x = 14
=> 5x + y = 14 .........(i)

When reversed, the number become
100x+10y+4x .............(ii)


SO,
(100×4x) + 10y + x - 100x - 10y - 4x = 594
=> 400x + x - 100x - 4x = 594
=> 300x-3x = 594
=> 297 x = 594
=> x = 2


PUTTING x = 2 in equation (i), we get :
5x = 14-y
=> 10 = 14-y
=> -y = 10-14
=> y = 4


At last, the number stands
XYZ
= 100X + 10Y + Z×1 (or Z)
= (4×2×100) + (4×10) + 2
= 800 + 40 + 2
= 842









SO, AT LAST ITS PROVED THAT I AM INTELLIGENT AARCHIIIIIIIIIIIIIIIIIIII..........!!!!!!!!!
HAPPY LEARNING.......!!!!!!!^__^ ^__^