Question

HEY FRND !!

need ur help !! plz help me....

☺☺☺

Answer 1

Hey Mate
You're Answer
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1.

Answer 2

1) You may refer to the Attachments...

2) Bond Order = 1/2[No. of Bonding Electron - No. of Antibonding Electron]

So, for calculating Bonding and Antibonding we are using a shortcut method..

Let's name Bonding Electron as B and Antibonding as A

B A B A B B B B A A A

And fill 2 electrons in each sequence wise First B then A then B then A and so on....

i) N2 = 14 Electrons

B A B A B B B A A A

2 2 2 2 2 2 2

So on A 4 electron are there and on B 10 electrons

So, 1/2[10-4]

= 3.. So B.O is 3

ii) O2 = 16

B A B A B B B A A A

2 2 2 2 2 2 2 2

A = 6

B = 10

So, B.O = 1/2[10-6]

= 2

iii) O2+ = 15

B A B A B B B A A A

2 2 2 2 2 2 2 1

A = 5

B = 10

So, B.O. = 1/2[10-5]

= 2.5

4) O2 2- = 18

B A B A B B B A A A

2 2 2 2 2 2 2 2 2

A = 8

B = 10

So, B.O. = 1/2[10-8]

= 1

v) O2 - = 17

B A B A B B B A A A

2 2 2 2 2 2 2 2 1

A = 7

B = 10

So, B.O. = 1/2[10-7]

= 1.5