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CALCULATE THE NO. OF ELECTON & NEUTRON IN 1.6g OF NAOH.???????
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✨Heya Sweety✌
✍Your answer⬇⬇⬇⬇
Moles of NaOH= Given wt./gram mol.wt.
= 1.6/39= 0.04 moles
Now,
No. of electrons =0.04×6.022×10^23×20
= 4.81×10^23
No. of Neutrons
=0.04×6.022×10^23×20
=4.81×10^23
Hope my answer satisfy u dear:)
If any doubt about this answer then ask in comment section
#Be Brainly
✍Your answer⬇⬇⬇⬇
Moles of NaOH= Given wt./gram mol.wt.
= 1.6/39= 0.04 moles
Now,
No. of electrons =0.04×6.022×10^23×20
= 4.81×10^23
No. of Neutrons
=0.04×6.022×10^23×20
=4.81×10^23
Hope my answer satisfy u dear:)
If any doubt about this answer then ask in comment section
#Be Brainly
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