Question

Hey frnds....
Here is your question....

Solve the attached..... redox reaction by ion electronics method.....
steps written in words.... are to be ignored.......

Appropriate answer will be marked brainliest...

Answer 1

Here it goes!!

MnO4- + C2O42- + H+ ---> Mn2+ + CO2

Step I

MnO4 - ----> Mn2+ + 4H2O

MnO4- + 8H+ ---> Mn2+ + 4H2O

MnO4- + 8H+ + 5e- ---> Mn2+ + 4H2O ---- (1)

Step II

C2O4^2- ---> CO2

C2O4^2- ---> 2CO2

C2O4^2- ---> 2CO2 +2e- ---- (2)

MnO4- + 8H+ + 5e- ---> Mn2+ + 4H2O ---- (1) x 2

C2O4^2- ---> 2CO2 +2e- ---- (2) x 5

Adding (1) +(2)

2MnO4- + 16H+ +10e- ---> 2Mn2+ + 8H2O ---- (1)

5C2O4^2- ---> 10CO2 +10e- ---- (2)

2MnO4- + 16H+ + 5C2O4^2- ---> 2Mn2+ + 8H2O + 10CO2

Hope that helped you!!