Question

Hey frnds! Need Help (*_*)

The population of a town increased by rate of 5% per year consecutively for 2 years. Then, due to an epidemic in the third year the population decreased at the rate of 1.5% for the next 3 years. What is the current population of that town if it was 23,45,000 Five years ago?

Answer 1

heya mate..!

here is your answer..

rate of interest=5%(increase)
time=2years
rate of interest=1.5%(decrease)
time=3years

present population=2345000*(1+5/100)(1+5/100)
(1-1.5/100)(1.1.5/100)(1-1.5/100)..

If you simply this equation,you'll get the answer..

hope it helps you..plz Mark as brainliest..

Answer 2

heya...

Here is your answer...

Given,

Rate in increase of a town population is 5%

Time = 2 years

Rate of decrease of a town population is 1.5%

Time = 3 years

Current population = 23,45,000×(1+5/100)(1+5/100)

It may help you....☺☺