Hey frnds pls answer me !! A car takes two hours less for a journey of 300 km,if its speed is increased by 5 km/ hr from its usual speed.Find usual speed
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Answered by
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Hola Friend ✋✋✋
Let the usual speed be ' x '
Time = Distance/ speed
Given
t = 300/x
if speed is increased
t - 2 = 300 / ( x + 5 )
so....
300/ x - 2 = 300 / ( x + 5 )
300/x - 300/(x + 5 ) = 2
(300x + 1500 - 300x) = 2x² + 10x
x² + 5x - 750 = 0
x = -5 ± √(3025) / 2
x = - 5 ± 55/2
x = -30, 25
Speed won't come in negative.... so usual speed is 25 km/h
Hope you will understand
Let the usual speed be ' x '
Time = Distance/ speed
Given
t = 300/x
if speed is increased
t - 2 = 300 / ( x + 5 )
so....
300/ x - 2 = 300 / ( x + 5 )
300/x - 300/(x + 5 ) = 2
(300x + 1500 - 300x) = 2x² + 10x
x² + 5x - 750 = 0
x = -5 ± √(3025) / 2
x = - 5 ± 55/2
x = -30, 25
Speed won't come in negative.... so usual speed is 25 km/h
Hope you will understand
Hemamalini15:
Thanks
Answered by
0
Answer:
Time= distance/speed
let unusual speed be x
so (300/x)-(300/x+5)=2
300{(x+5)-x}=2(x+5)x
1500=2x(x+5)
x(x+5)=750
(x^2)+5x-750=0
from this equation, we can find the two zeroes for the equation as -30 and 25
as speed can never be negative,
so x=25 kmph
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