Question

hey frnds pls help mee.....
i need urgent plss

Answer 1

ʜᴏᴩᴇ ɪᴛ ʜᴇʟᴩꜱ yᴏᴜ ):(

Answer 2

$\underline{\mathsf{ Solution : }}$

$\mathsf{ = \: 2 \: log_{10}(sin \: x) \: + \: 2 \: log_{10}(cosec \: x) } \\ \\ \mathsf{ Taking\: out \: 2 \: common \: factor : } \\ \\ \mathsf{= 2[ log_{10}( sin \: x ) \: + \: log_{10}( cosec \: x ) ]}$

$\mathsf{ Using \: identity : } \\ \\ \boxed{\mathsf{ \implies log_{a}(b) \: + \: log_{a}(c) \: = \: log_{a}(bc) \: }} \\ \\ \mathsf{ = 2[ log_{10}( sin \: x \: \times \: cosec \: x) ] } \\ \\ \mathsf{ Using \: trigonometric \: identity : } \\ \\ \boxed{\mathsf{ \implies sin \: \theta \: \times \: cosec \: \theta \: = \: 1 \: }} \\ \\ \mathsf{ = 2[ log_{10}(1)] } \\ \\ \mathsf{ = 2[0] } \\ \\ \mathsf{ = 0 }$